For the reactions, I. CH4(g) xrightarrow[]C(g)+4H(g) ; Δ H=x1 II. C2H6(g) xrightarrow[]2C(g)+6H(g);Δ H=x2 from I and II, bond energy of C-C bond is

Question

For the reactions, I. CH4(g) xrightarrow[]C(g)+4H(g) ; Δ H=x1 II. C2H6(g) xrightarrow[]2C(g)+6H(g);Δ H=x2 from I and II, bond energy of C-C bond is (A)  x1-x2 (B) x2-x1  (C) x2+1.5x1  (D)  x2-1.5x1

Tardigrade Admin · Accepted Answer

(I) CH4(g) xrightarrow[]C(g)+4H(g) Δ H=x text for text four text C-H text bonds. ∴ BE of (C-H) bond =(x1/4) (II) C6H6(g) xrightarrow[]2C(g)+6H(g) Δ H=x2=(BE)C-C+6(BE)C-H x2=BEC-C+6× (x1/4) (BE)C-C=x2-1.5x1

Q. For the reactions, I. $C H_{4} (g) C (g) + 4 H (g); Δ H = x_{1}$
II. $C_{2} H_{6} (g) 2 C (g) + 6 H (g); Δ H = x_{2}$
from I and II, bond energy of $C - C$ bond is

$x_{1} - x_{2}$

$x_{2} - x_{1}$

$x_{2} + 1.5 x_{1}$

$x_{2} - 1.5 x_{1}$

(I) $C H_{4} (g) C (g) + 4 H (g)$
$Δ H = x f or f o u r C - H b o n d s .$
$∴$ BE of $(C - H)$ bond $= \frac{x _{1}}{4}$
(II) $C_{6} H_{6} (g) 2 C (g) + 6 H (g)$
$Δ H = x_{2} = (BE)_{C - C} + 6 (BE)_{C - H}$
$x_{2} = B E_{C - C} + 6 \times \frac{x _{1}}{4}$
$(BE)_{C - C} = x_{2} - 1.5 x_{1}$

Q. For the reactions, I. CH4​(g)​C(g)+4H(g);ΔH=x1​ II. C2​H6​(g)​2C(g)+6H(g);ΔH=x2​ from I and II, bond energy of C−C bond is

x1​−x2​

x2​−x1​

x2​+1.5x1​

x2​−1.5x1​