Question

For the reaction, $N_2{O}_4(g)\rightleftharpoons 2N{O}_2(g)$ ; if percentage dissociation of $N_2{O}_4$ are 25%, 50%, 75% and 100, then the sequence of observed vapour densities will be

• A. $d_{25}>d_{50}>d_{75}>d_{100}$
• B. $d_{100}>d_{75}>d_{50}>d_{25}$
• C. $d_{25}=d_{50}=d_{75}=d_{100}$
• D. $(d_{25}=d_{50})>(d_{75}=d_{100})$

Answer 1

Answer: (A)

Here the reaction, $N_2{O}_4(g)\rightleftharpoons 2N{O}_2(g)$ ;
As $\alpha =\frac{D-d}{(n-1)d}$ (Here d = vapour density or density after dissociation)
As percentage dissociation of $d_{25}>d_{50}>d_{75}>d_{100}$