For the reaction, N2(g)+3 H2(g) leftharpoons 2 N H3(g) at 400 K, Kp=41 . Find the value for the following reaction, (1/2) N 2(g)+(3/2) H 2(g) leftharpoons NH 3(g)

Question

For the reaction, N2(g)+3 H2(g) leftharpoons 2 N H3(g) at 400 K, Kp=41 . Find the value for the following reaction, (1/2) N 2(g)+(3/2) H 2(g) leftharpoons NH 3(g) (A) 6.4 (B) 0.02 (C) 50 (D) 4.6

Tardigrade Admin · Accepted Answer

Given, N2(g)+3 H2(g) leftharpoons 2 N H3(g) ;KP=41 Kp=(pN H32/pN2 pH23)=41 ... (i) For reaction, (1/2) N2(g)+(3/2) H2(g) leftharpoons N H3(g), Kp'=(pN H3/pN21 / 2 pH23 / 2) ... (ii) On squaring both sides, we get (Kp')2=(pN H32/pN2 pH23) ...(iii) On dividing Eq. (i) by Eq. (iii), we get Kp'=√Kp=√41=6.4

Q. For the reaction, N2​(g)+3H2​(g)⇌2NH3​(g) at 400K,Kp​=41. Find the value for the following reaction, 21​N2​(g)+23​H2​(g)⇌NH3​(g)

6.4

0.02

50

4.6

Q. For the reaction,
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$ at $400 K, K_{p} = 41.$ Find the value for the following reaction,
$\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ N H_{3} (g)$