For the reaction N2+3H2 arrow 2NH3 if (Δ[NH3]/Δ t)=2×10-4 mol l-1s-1, then value of (-Δ[H2]/Δ t) would be

Question

For the reaction N2+3H2 arrow 2NH3 if (Δ[NH3]/Δ t)=2×10-4 mol l-1s-1, then value of (-Δ[H2]/Δ t) would be (A) 1 × 10-4 mol L-1s-1 (B) 3 × 10-4 mol L-1s-1 (C) 4 × 10-4 mol L-1s-1 (D) 6 × 10-4 mol L-1s-1

Tardigrade Admin · Accepted Answer

N2+3H2 arrow 2NH3 (-[N2]/Δ t)=(1/3) (Δ[H2]/Δ t)=(1/2) (Δ[NH3]/Δ t) ∴ (-Δ[H2]/Δ t)=(3/2)×(Δ[NH3]/Δ t)=(3/2)×2×10-4 =3×10-4 mol L-1S-1

Q. For the reaction $N_{2} + 3 H_{2} \to 2 N H_{3}$
if $\frac{Δ [ N H _{3} ]}{Δ t} = 2 \times 1 0^{- 4} m o l l^{- 1} s^{- 1},$ then value of $\frac{- Δ [ H _{2} ]}{Δ t}$ would be

$1 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$3 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$4 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$6 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

Q. For the reaction N2​+3H2​→2NH3​ if ΔtΔ[NH3​]​=2×10−4moll−1s−1, then value of Δt−Δ[H2​]​ would be

1×10−4molL−1s−1

3×10−4molL−1s−1

4×10−4molL−1s−1

6×10−4molL−1s−1

N2​+3H2​→2NH3​ Δt−[N2​]​=31​ΔtΔ[H2​]​=21​ΔtΔ[NH3​]​ ∴Δt−Δ[H2​]​=23​×ΔtΔ[NH3​]​=23​×2×10−4 =3×10−4molL−1S−1

Q. For the reaction $N_{2} + 3 H_{2} \to 2 N H_{3}$
if $\frac{Δ [ N H _{3} ]}{Δ t} = 2 \times 1 0^{- 4} m o l l^{- 1} s^{- 1},$ then value of $\frac{- Δ [ H _{2} ]}{Δ t}$ would be

$1 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$3 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$4 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$

$6 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$