Question

For the reaction $H_{2}O(l)\leftrightharpoons H_{2}O(g)$ at $373K$ and one atmospheric pressure

• A. $\Delta H=T\Delta S$
• B. $\Delta H=\Delta E$
• C. $\Delta H=\Delta 0$
• D. $\Delta E=\Delta 0$

Answer 1

Answer: (A)

$\Delta G=\Delta H-T\cdot \Delta S$

For the reaction,

$H_{2}O(l)\rightleftharpoons H_{2}O(g)$

$\Delta G=0$(at equilibrium)

$\therefore \Delta H=T\cdot \Delta S$