Question

For the reaction $H_{2}O(l)\rightleftharpoons H_{2}O(g)$ at $373K$ and $1$ atm pressure

• A. $\Delta H=0$
• B. $\Delta E=0$
• C. $\Delta H=T\Delta S$
• D. $\Delta H=\Delta E$

Answer 1

Answer: (C)

$\Delta G=\Delta H-T\cdot \Delta S$
For the reaction,
$H_{2}O(l)\rightleftharpoons H_{2}O(g)$
$\Delta G=0$ (at equilibrium)
$\therefore \Delta H=T\cdot \Delta S$