For the reaction H2(g) + I2(g) leftharpoons 2HI(g) at 721 K the value of equilibrium constant (Kc) is 50. When the equilibrium concentration of both is 0.5 M, the value of Kp under the same conditions will be

Question

For the reaction H2(g) + I2(g) leftharpoons 2HI(g) at 721 K the value of equilibrium constant (Kc) is 50. When the equilibrium concentration of both is 0.5 M, the value of Kp under the same conditions will be (A) 0 .002 (B) 0.2 (C) 50.0 (D) 50/RT

Tardigrade Admin · Accepted Answer

For the reaction H2 +I2 leftharpoons 2HI Δ n = O So Kp = Kc ∴ 50.0

Q. For the reaction $H_{2} (g) + I_{2} (g) ⇌ 2 H I (g)$ at $721 K$ the value of equilibrium constant $(K_{c})$ is $50$ . When the equilibrium concentration of both is $0.5 M$ , the value of $K_{p}$ under the same conditions will be

$0.002$

$0.2$

$50.0$

$50/ RT$

For the reaction $H_{2} + I_{2} ⇌ 2 H I$
$Δ n = O$
$S o K_{p} = K_{c} ∴ 50.0$

Q. For the reaction H2​(g)+I2​(g)⇌2HI(g) at 721K the value of equilibrium constant (Kc​) is 50. When the equilibrium concentration of both is 0.5M, the value of Kp​ under the same conditions will be

0.002

0.2

50.0

50/RT