For the reaction Fe2O3 +3CO arrow 2Fe + 3CO2 the volume of carbon monoxide required to reduce one mole of ferric oxide is

Question

For the reaction Fe2O3 +3CO arrow 2Fe + 3CO2 the volume of carbon monoxide required to reduce one mole of ferric oxide is (A) 22.4 dm3 (B) 44.8 dm3 (C) 67.2 dm3 (D) 11.2 dm3

Tardigrade Admin · Accepted Answer

underset1 mol Fe 2O3+ underset3 mol 3 CO longrightarrow 2 Fe +3 CO 2 Volume of 1 mole carbon monoxide = 22.4 L (at STP) 1 mole of ferric oxide is reduced by = 3 moles of CO =3 × 22.4 L of CO =67.2 dm 3 of CO

Q. For the reaction $F e_{2} O_{3} + 3 CO \to 2 F e + 3 C O_{2}$ the volume of carbon monoxide required to reduce one mole of ferric oxide is

$22.4 d m^{3}$

$44.8 d m^{3}$

$67.2 d m^{3}$

$11.2 d m^{3}$

$1 m o l F e_{2} O_{3} + 3 m o l 3 CO ⟶ 2 F e + 3 C O_{2}$

Volume of $1 m o l e$ carbon monoxide

$= 22.4 L$ (at STP)

$1$ mole of ferric oxide is reduced by $= 3$ moles of $CO$

$= 3 \times 22.4 L$ of $CO$

$= 67.2 d m^{3}$ of $CO$

Q. For the reaction Fe2​O3​+3CO→2Fe+3CO2​ the volume of carbon monoxide required to reduce one mole of ferric oxide is

22.4dm3

44.8dm3

67.2dm3

11.2dm3