For the reaction equilibrium, N2O4(g)2NO(g) the concentrations of N2O4 and NO2 at equilibrium are 4.8× 10-2 and 1.2× 10-2mol L-1 respectively. The value of Kc for the reaction is

Question

For the reaction equilibrium, N2O4(g)2NO(g) the concentrations of N2O4 and NO2 at equilibrium are 4.8× 10-2 and 1.2× 10-2mol L-1 respectively. The value of Kc for the reaction is (A)  3.3× 102mol L-1  (B)  3× 10-1mol L-1  (C)  3× 10-3mol L-1  (D)  3× 103mol L-1

Tardigrade Admin · Accepted Answer

Kc=([NO2]2/[N2O4])=((1.2× 10-2)2/4.8× 10-2) =3× 10-3mol L-1

Q. For the reaction equilibrium, $N_{2} O_{4} (g) 2 NO (g)$ the concentrations of $N_{2} O_{4}$ and $N O_{2}$ at equilibrium are $4.8 \times 10^{- 2}$ and $1.2 \times 10^{- 2} m o l L^{- 1}$ respectively. The value of $K_{c}$ for the reaction is

$3.3 \times 10^{2} m o l L^{- 1}$

$3 \times 10^{- 1} m o l L^{- 1}$

$3 \times 10^{- 3} m o l L^{- 1}$

$3 \times 10^{3} m o l L^{- 1}$

$K_{c} = \frac{[ N O _{2} ] ^{2}}{[ N _{2} O _{4} ]} = \frac{( 1.2 \times 10 ^{- 2} ) ^{2}}{4.8 \times 10 ^{- 2}}$ $= 3 \times 10^{- 3} m o l L^{- 1}$

Q. For the reaction equilibrium, N2​O4​(g)2NO(g) the concentrations of N2​O4​ and NO2​ at equilibrium are 4.8×10−2 and 1.2×10−2molL−1 respectively. The value of Kc​ for the reaction is

3.3×102molL−1

3×10−1molL−1

3×10−3molL−1

3×103molL−1