For the reaction CH4(g) + 2O2(g) arrow CO2(g) + 2H2O(l) Δ H°f of CH4(g), CO2(g) and H2O(l) is respectively -x, -y and -z kJ mol-1. Enthalpy change (∆r°H) for the reaction is

Question

For the reaction CH4(g) + 2O2(g) arrow CO2(g) + 2H2O(l) Δ H°f of CH4(g), CO2(g) and H2O(l) is respectively -x, -y and -z kJ mol-1. Enthalpy change (∆r°H) for the reaction is (A) x + y + 2z (B) x - y - 2z (C) y - x + 2z (D) y + z - x

Tardigrade Admin · Accepted Answer

Δ Hor=∑Δ Hfo = of products -∑Δ Hfo of reactants

Q. For the reaction $C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l)$
$Δ H_{f}^{°} o f C H_{4} (g), C O_{2} (g) an d H_{2} O (l)$ is respectively -x, -y and -z kJ $m o l^{- 1}$ . Enthalpy change $(∆_{r}^{°} H)$ for the reaction is

x + y + 2z

x - y - 2z

y - x + 2z

y + z - x

$Δ H_{r}^{o} = \sum Δ H_{f}^{o}$ = of products $- \sum Δ H_{f}^{o}$ of reactants

Q. For the reaction CH4​(g)+2O2​(g)→CO2​(g)+2H2​O(l) ΔHf°​ofCH4​(g),CO2​(g)andH2​O(l) is respectively -x, -y and -z kJ mol−1. Enthalpy change (∆r°​H) for the reaction is