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Tardigrade
Question
Chemistry
For the reaction, C3H8(g)+5O2(g) xrightarrow3CO2(g)+4H2O(l) at constant temperature, Δ H-Δ E is
Q. For the reaction,
C
3
H
8
(
g
)
+
5
O
2
(
g
)
3
C
O
2
(
g
)
+
4
H
2
O
(
l
)
at constant temperature,
Δ
H
−
Δ
E
is
2291
175
Jharkhand CECE
Jharkhand CECE 2013
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A
+
3
RT
B
−
RT
C
+
RT
D
−
3
RT
Solution:
For the given reaction,
Δ
n
g
=
n
p
−
n
R
=
3
−
6
=
−
3
Δ
H
=
Δ
E
+
Δ
n
g
RT
Δ
H
−
Δ
E
=
Δ
n
g
RT
Δ
H
−
Δ
E
=
−
3
RT