For the reaction; A(s)→ B(g) + C(g) ΔrG° =(1000 -50 T ln T) ΔrG°p of the above reaction in kJ/mol is 10 X. Find the value of X

Question

For the reaction; A(s)→ B(g) + C(g) ΔrG° =(1000 -50 T ln T) ΔrG°p of the above reaction in kJ/mol is 10 X. Find the value of X (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

ΔrG° = 1000 - 50 T ln T (d(Δr G°)/dT) = - ΔrS° = -50 ln T - 50 ∴ ΔrH° = ΔrG° + TΔrS° or ΔrH° = ΔrG° + T(+50 ln T + 50) or ΔrH° = 1000 - 50 T ln T +50 T ln T + 50 T or ΔrH° = 1000 + 50 T or ΔrC°p =(d/dT)(ΔrH°) = 50 kJ/mol = 10X ⇒ X=5

Q. For the reaction; A(s)→B(g)+C(g) Δr​G∘=(1000−50TlnT) Δr​Gp∘​ of the above reaction in kJ/mol is 10X. Find the value of X

Δr​G∘=1000−50TlnT dTd(Δr​G∘)​=−Δr​S∘=−50lnT−50 ∴Δr​H∘=Δr​G∘+TΔr​S∘ or Δr​H∘=Δr​G∘+T(+50lnT+50) or Δr​H∘=1000−50TlnT+50TlnT+50T or Δr​H∘=1000+50T or Δr​Cp∘​=dTd​(Δr​H∘) =50kJ/mol=10X ⇒X=5

Q. For the reaction;
$A (s) \to B (g) + C (g)$
$Δ_{r} G^{\circ} = (1000 - 50 Tl n T)$
$Δ_{r} G_{p}^{\circ}$ of the above reaction in kJ/mol is $10 X$ . Find the value of $X$