For the reaction 2NO2(g) leftharpoons 2 NO(g) + O2(g) (Kc = 1.8×10-6 at 184°C) (R = 0.00831 k J/(mol. K)) When Kp and Kc are compared at 184° C it is found that :

Question

For the reaction 2NO2(g) leftharpoons 2 NO(g) + O2(g) (Kc = 1.8×10-6 at 184°C) (R = 0.00831 k J/(mol. K)) When Kp and Kc are compared at 184° C it is found that : (A) whether Kp is greater than, less than or equal to Kc depends upon the total gas pressure (B) Kp = Kc (C) Kp is less than Kc (D) Kp is greater than Kc

Tardigrade Admin · Accepted Answer

2NO2(g) leftharpoons 2 NO(g) + O2(g) Kc = 1.8×10-6 at 184°C ( = 457 K) R = 0.00831 k J mol-1 K-1 Kp=Kc(RT)Δ ng where, Δ ng = (gaseous products - gaseous reactants) =3-2=1 ∴ Kp = 1.8 × 10-6 × 0.00831 × 457 = 6.836 ×10-6 > 1.8 ×10-6 Thus Kp > Kc

Q. For the reaction
$2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$
$(K_{c} = 1.8 \times 1 0^{- 6} a t 18 4^{\circ} C)$
$(R = 0.00831 k J / (m o l . K))$
When $K_{p}$ and $K_{c}$ are compared at $18 4^{\circ}$ C it is found that :

whether $K_{p}$ is greater than, less than or equal to $K_{c}$ depends upon the total gas pressure

$K_{p} = K_{c}$

$K_{p}$ is less than $K_{c}$

$K_{p}$ is greater than $K_{c}$

Q. For the reaction 2NO2​(g)⇌2NO(g)+O2​(g) (Kc​=1.8×10−6at184∘C) (R=0.00831kJ/(mol.K)) When Kp​ and Kc​ are compared at 184∘ C it is found that :

whether Kp​ is greater than, less than or equal to Kc​ depends upon the total gas pressure

Kp​=Kc​

Kp​ is less than Kc​

Kp​ is greater than Kc​

2NO2​(g)⇌2NO(g)+O2​(g) Kc​=1.8×10−6at184∘C(=457K) R=0.00831kJmol−1K−1 Kp​=Kc​(RT)Δng​ where, Δng​= (gaseous products - gaseous reactants) =3−2=1 ∴Kp​=1.8×10−6×0.00831×457 =6.836×10−6>1.8×10−6 Thus Kp​>Kc​

Q. For the reaction
$2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$
$(K_{c} = 1.8 \times 1 0^{- 6} a t 18 4^{\circ} C)$
$(R = 0.00831 k J / (m o l . K))$
When $K_{p}$ and $K_{c}$ are compared at $18 4^{\circ}$ C it is found that :

whether $K_{p}$ is greater than, less than or equal to $K_{c}$ depends upon the total gas pressure

$K_{p} = K_{c}$

$K_{p}$ is less than $K_{c}$

$K_{p}$ is greater than $K_{c}$