For the reaction, 2 NO 2(g) leftharpoons 2 NO (g)+ O 2(g) (Kc=1.8 × 10-6. at 184° C and R =0.00831 kJ / mol K ) When Kp and Kc are compared at 184° C, it is found that

Question

For the reaction, 2 NO 2(g) leftharpoons 2 NO (g)+ O 2(g) (Kc=1.8 × 10-6. at 184° C and R =0.00831 kJ / mol K ) When Kp and Kc are compared at 184° C, it is found that (A) whether Kp is greater than less than or equal to Kc depends uupon the total gas pressure (B) Kp=Kc (C) Kp is less than Kc (D) Kp is greater than Kc

Tardigrade Admin · Accepted Answer

2 NO 2(g)=2 NO (g)+ O 2(g) Kc=1.8 × 10-6 at 184° C (=457 K ) R=0.00831 kJ mol -1 K -1 Kp=Kc(R T)Δ ng where, Δ ng= (gaseous products -gaseous reactants) =3-2=1 ∴ Kp=1.8 × 10-6 × 0.00831 × 457 =6.836 × 10-6 >1.8 × 10-6 Thus, Kp > Kc

Q. For the reaction, $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$ $(K_{c} = 1.8 \times 1 0^{- 6}$ at $18 4^{\circ} C$ and R $= 0.00831 k J / m o l K$ ) When $K_{p}$ and $K_{c}$ are compared at $18 4^{\circ} C$ , it is found that

whether $K_{p}$ is greater than less than or equal to $K_{c}$ depends uupon the total gas pressure

$K_{p} = K_{c}$

$K_{p}$ is less than $K_{c}$

$K_{p}$ is greater than $K_{c}$

Q. For the reaction, 2NO2​(g)⇌2NO(g)+O2​(g) (Kc​=1.8×10−6 at 184∘C and R =0.00831kJ/molK ) When Kp​ and Kc​ are compared at 184∘C, it is found that

whether Kp​ is greater than less than or equal to Kc​ depends uupon the total gas pressure

Kp​=Kc​

Kp​ is less than Kc​

Kp​ is greater than Kc​

2NO2​(g)=2NO(g)+O2​(g) Kc​=1.8×10−6 at 184∘C(=457K) R=0.00831kJmol−1K−1 Kp​=Kc​(RT)Δng​ where, Δng​= (gaseous products -gaseous reactants) =3−2=1 ∴Kp​=1.8×10−6×0.00831×457 =6.836×10−6>1.8×10−6 Thus, Kp​>Kc​

Q. For the reaction, $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$ $(K_{c} = 1.8 \times 1 0^{- 6}$ at $18 4^{\circ} C$ and R $= 0.00831 k J / m o l K$ ) When $K_{p}$ and $K_{c}$ are compared at $18 4^{\circ} C$ , it is found that

whether $K_{p}$ is greater than less than or equal to $K_{c}$ depends uupon the total gas pressure

$K_{p} = K_{c}$

$K_{p}$ is less than $K_{c}$

$K_{p}$ is greater than $K_{c}$