For the reaction 2NO2(g)leftharpoons 2NO(g)+O2(g) Kc=1.8× 10-6 at 185° C. At 185° C, the Kc for reaction NO(g)+(1/2)(O2) (g)leftharpoons NO2(g)is:

Question

For the reaction 2NO2(g)leftharpoons 2NO(g)+O2(g) Kc=1.8× 10-6 at 185° C. At 185° C, the Kc for reaction NO(g)+(1/2)(O2) (g)leftharpoons NO2(g)is:  (A)  1.95× 10-3  (B)  1.95× 103  (C)  7.5× 102  (D)  0.9× 106

Tardigrade Admin · Accepted Answer

2NO2(g)leftharpoons 2NO(g)+O2(g) Kc=([NO]2[O2]/[NO2]2)=1.8× 10-6 For reaction (1/2)O2(g)+NO(g)leftharpoons NO2(g) Kc=([NO2]/[O2]1/2[NO])=√(1/Kc) =√(1/1.8× 10-6)=√0.56× 10-6 =0.75× 103=7.5× 102

Q. For the reaction $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$ $K_{c} = 1.8 \times 10^{- 6}$ at $185^{\circ} C .$ At $185^{\circ} C,$ the $K_{c}$ for reaction $NO (g) + \frac{1}{2} (O_{2}) (g) ⇌ N O_{2} (g) i s :$

$1.95 \times 10^{- 3}$

$1.95 \times 10^{3}$

$7.5 \times 10^{2}$

$0.9 \times 10^{6}$

Q. For the reaction 2NO2​(g)⇌2NO(g)+O2​(g) Kc​=1.8×10−6 at 185∘C. At 185∘C, the Kc​ for reaction NO(g)+21​(O2​)(g)⇌NO2​(g)is:

1.95×10−3

1.95×103

7.5×102

0.9×106

2NO2​(g)⇌2NO(g)+O2​(g) Kc​=[NO2​]2[NO]2[O2​]​=1.8×10−6 For reaction 21​O2​(g)+NO(g)⇌NO2​(g) Kc​=[O2​]1/2[NO][NO2​]​=Kc​1​​ =1.8×10−61​​=0.56×10−6​ =0.75×103=7.5×102

Q. For the reaction $2 N O_{2} (g) ⇌ 2 NO (g) + O_{2} (g)$ $K_{c} = 1.8 \times 10^{- 6}$ at $185^{\circ} C .$ At $185^{\circ} C,$ the $K_{c}$ for reaction $NO (g) + \frac{1}{2} (O_{2}) (g) ⇌ N O_{2} (g) i s :$

$1.95 \times 10^{- 3}$

$1.95 \times 10^{3}$

$7.5 \times 10^{2}$

$0.9 \times 10^{6}$