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Q. For the reaction $ 2N{{O}_{2}}(g)\rightleftharpoons 2NO(g)+{{O}_{2}}(g) $ $ {{K}_{c}}=1.8\times {{10}^{-6}} $ at $ 185{}^\circ C. $ At $ 185{}^\circ C, $ the $ {{K}_{c}} $ for reaction $ NO(g)+\frac{1}{2}({{O}_{2}})\,(g)\rightleftharpoons N{{O}_{2}}(g)is: $

JIPMERJIPMER 2001Equilibrium

Solution:

$ 2N{{O}_{2}}(g)\rightleftharpoons 2NO(g)+{{O}_{2}}(g) $ $ {{K}_{c}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}=1.8\times {{10}^{-6}} $ For reaction $ \frac{1}{2}{{O}_{2}}(g)+NO(g)\rightleftharpoons N{{O}_{2}}(g) $ $ K_{c}^{}=\frac{[N{{O}_{2}}]}{{{[{{O}_{2}}]}^{1/2}}[NO]}=\sqrt{\frac{1}{{{K}_{c}}}} $ $ =\sqrt{\frac{1}{1.8\times {{10}^{-6}}}}=\sqrt{0.56\times {{10}^{-6}}} $ $ =0.75\times {{10}^{3}}=7.5\times {{10}^{2}} $