For the reaction, 2Cl(g) xrightarrowCl2(g), the signs of Δ H and Δ S are

Question

For the reaction, 2Cl(g) xrightarrowCl2(g), the signs of Δ H and Δ S are (A)  Δ H=+ve, Δ S=-ve  (B)  Δ H=-ve, Δ S=+ve  (C)  Δ H=+ve, Δ S=+ve  (D)  Δ H=-ve, Δ S=-ve

Tardigrade Admin · Accepted Answer

Δ H is negative (bond energy is released) and Δ S is negative (There is less randomness among the

Q. For the reaction, $2 Cl (g) C l_{2} (g),$ the signs of $Δ H$ and $Δ S$ are

$Δ H = + v e, Δ S = - v e$

$Δ H = - v e, Δ S = + v e$

$Δ H = + v e, Δ S = + v e$

$Δ H = - v e, Δ S = - v e$

$Δ H$ is negative (bond energy is released) and $Δ S$ is negative (There is less randomness among the

Q. For the reaction, 2Cl(g)​Cl2​(g), the signs of ΔH and ΔS are

ΔH=+ve,ΔS=−ve

ΔH=−ve,ΔS=+ve

ΔH=+ve,ΔS=+ve

ΔH=−ve,ΔS=−ve