For the reaction 2 A +3 B +(3/2) C → 3 P , which statement is correct ?

Question

For the reaction 2 A +3 B +(3/2) C → 3 P , which statement is correct ? (A) ( dn A / dt )=( dn B / dt )=( dn C / dt ) (B) ( dn A / dt )=(2/3) ( dn B / dt )=(3/4) ( dn C / dt ) (C) ( dn A / dt )=(3/2) ( dn B / dt )=(3/4) ( dn C / dt ) (D) ( dn A / dt )=(2/3) ( dn B / dt )=(4/3) ( dn C / dt )

Tardigrade Admin · Accepted Answer

For a A+b B arrow c C (-1/a) (d[A]/d t)=(-1/b) (d[B]/d t)=(1/c) (d[C]/d t) ∴ (-1/2) ( d [ A ]/ dt )=(-1/3) ( d [ B ]/ dt )=(-2/3) ( d [ C ]/ dt )=(1/3) ( d [ P ]/ dt )

Q. For the reaction $2 A + 3 B + \frac{3}{2} C \to 3 P,$ which statement is correct ?

$\frac{d n _{A}}{d t} = \frac{d n _{B}}{d t} = \frac{d n _{C}}{d t}$

$\frac{d n _{A}}{d t} = \frac{2}{3} \frac{d n _{B}}{d t} = \frac{3}{4} \frac{d n _{C}}{d t}$

$\frac{d n _{A}}{d t} = \frac{3}{2} \frac{d n _{B}}{d t} = \frac{3}{4} \frac{d n _{C}}{d t}$

$\frac{d n _{A}}{d t} = \frac{2}{3} \frac{d n _{B}}{d t} = \frac{4}{3} \frac{d n _{C}}{d t}$

For $a A + b B \to c C$

$\frac{- 1}{a} \frac{d [ A ]}{d t} = \frac{- 1}{b} \frac{d [ B ]}{d t} = \frac{1}{c} \frac{d [ C ]}{d t}$

$∴ \frac{- 1}{2} \frac{d [ A ]}{d t} = \frac{- 1}{3} \frac{d [ B ]}{d t} = \frac{- 2}{3} \frac{d [ C ]}{d t} = \frac{1}{3} \frac{d [ P ]}{d t}$

Q. For the reaction 2A+3B+23​C→3P, which statement is correct ?

dtdnA​​=dtdnB​​=dtdnC​​

dtdnA​​=32​dtdnB​​=43​dtdnC​​

dtdnA​​=23​dtdnB​​=43​dtdnC​​

dtdnA​​=32​dtdnB​​=34​dtdnC​​