For the molecules LiF , N2 , K2O and ClF3 , what is the correct arrangement of bonds in order of increasing ionic character?

Question

For the molecules LiF , N2 , K2O and ClF3 , what is the correct arrangement of bonds in order of increasing ionic character? (A)  N2 < K2O < ClF3 < LiF  (B)  N2 < ClF3 < K2O < LiF  (C)  ClF3 < N2 < K2O < LiF  (D)  ClF3 < K2O < N2 < LiF

Tardigrade Admin · Accepted Answer

The ionic character of a molecule depends upon the electronegativity difference between the constituting atoms. Greater the difference, greater will be the ionic character of the molecule. Hence, the correct arrangement of bonds in increasing order of ionic character is:

N_{2} < Cl F_{3} < K_{2} O < L i F

Q. For the molecules $L i F$ , $N_{2}$ , $K_{2} O$ and $Cl F_{3}$ , what is the correct arrangement of bonds in order of increasing ionic character?

$N_{2} < K_{2} O < Cl F_{3} < L i F$

$N_{2} < Cl F_{3} < K_{2} O < L i F$

$Cl F_{3} < N_{2} < K_{2} O < L i F$

$Cl F_{3} < K_{2} O < N_{2} < L i F$

Q. For the molecules LiF , N2​ , K2​O and ClF3​ , what is the correct arrangement of bonds in order of increasing ionic character?

N2​<K2​O<ClF3​<LiF

N2​<ClF3​<K2​O<LiF

ClF3​<N2​<K2​O<LiF

ClF3​<K2​O<N2​<LiF

The ionic character of a molecule depends upon the electronegativity difference between the constituting atoms. Greater the difference, greater will be the ionic character of the molecule. Hence, the correct arrangement of bonds in increasing order of ionic character is: N2​<ClF3​<K2​O<LiF

Q. For the molecules $L i F$ , $N_{2}$ , $K_{2} O$ and $Cl F_{3}$ , what is the correct arrangement of bonds in order of increasing ionic character?

$N_{2} < K_{2} O < Cl F_{3} < L i F$

$N_{2} < Cl F_{3} < K_{2} O < L i F$

$Cl F_{3} < N_{2} < K_{2} O < L i F$

$Cl F_{3} < K_{2} O < N_{2} < L i F$