Tardigrade
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Tardigrade
Question
Physics
For the given cyclic process CAB as shown for a gas, the work done is :
Q. For the given cyclic process
C
A
B
as shown for a gas, the work done is :
3999
241
JEE Main
JEE Main 2019
Thermodynamics
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A
1 J
7%
B
5 J
18%
C
10 J
43%
D
30 J
32%
Solution:
Since P-V indicator diagram is given, so work done by gas is area under the cyclic diagram.
∴
Δ
W
=
Work done by gas
=
2
1
×
4
×
5
J
=
10
J