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Q. For the given cyclic process $CAB$ as shown for a gas, the work done is :Physics Question Image

JEE MainJEE Main 2019Thermodynamics

Solution:

Since P-V indicator diagram is given, so work done by gas is area under the cyclic diagram.
$\therefore \Delta W = $ Work done by gas $ =\frac{1}{2} \times4 \times5 J $
$ = 10\,J $