Question

For the given circuit, the equivalent capacitance between points $P$ and $Q$ is

• A. 6C
• B. 4C
• C. $\frac{3}{2}C$
• D. $\frac{6}{11}C$

Answer 1

Answer: (D)

$\therefore \frac{1}{C_{eq}}=\frac{1}{3C}+\frac{1}{2C}+\frac{1}{C}$
$=\frac{2+3+6}{6C}=\frac{11}{6C}$
$\therefore C_{eq}=\frac{6C}{11}$