For the gas phase reaction, PCl5(.g.)leftharpoons PCl3(.g.)+Cl2(.g.) Which of the following conditions are correct?

Question

For the gas phase reaction, PCl5(.g.)leftharpoons PCl3(.g.)+Cl2(.g.) Which of the following conditions are correct? (A) Δ H < 0 and Δ S < 0 (B) Δ H>0 and Δ S < 0 (C) Δ H=0 and Δ S < 0 (D) Δ H>0 and Δ S>0

Tardigrade Admin · Accepted Answer

Gas phase reaction PCl5(.g.)leftharpoons PCl3(.g.)+Cl2(.g.) Δ H=Δ E+Δ ngRT Δ n= change in number of moles of product and reactant species. Since Δ ng=+ve, hence Δ H=+ve also one mole of PCl5 is dissociated into two moles of PCl3 and Cl2 in the same phase. Therefore, Δ S=Sp r o d u c t-Sr e a c t a n t Δ S=+ve

Q. For the gas phase reaction,

$PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)$

Which of the following conditions are correct?

$Δ H < 0$ and $Δ S < 0$

$Δ H > 0$ and $Δ S < 0$

$Δ H = 0$ and $Δ S < 0$

$Δ H > 0$ and $Δ S > 0$

Q. For the gas phase reaction, PCl5​(g)⇌PCl3​(g)+Cl2​(g) Which of the following conditions are correct?

ΔH<0 and ΔS<0

ΔH>0 and ΔS<0

ΔH=0 and ΔS<0

ΔH>0 and ΔS>0

Q. For the gas phase reaction,

$PC l_{5} (g) ⇌ PC l_{3} (g) + C l_{2} (g)$

Which of the following conditions are correct?

$Δ H < 0$ and $Δ S < 0$

$Δ H > 0$ and $Δ S < 0$

$Δ H = 0$ and $Δ S < 0$

$Δ H > 0$ and $Δ S > 0$