Q.
For the function f(x)=34x3−8x2+16x+5,x=2isapointof
2224
193
AMUAMU 2010Application of Derivatives
Report Error
Solution:
f(x)=34x3−8x2+16x+5…(i)
There will be a point of inflexion at point x
if (dx2d2y)at(x=2)=0, but dx3d3y=0
From Eq. (i), f′(x)=4x2−16x+16 f′′(x)=8x−16 f′′(2)=16−16=0
and f′′(x)=8=0
Hence, at x=2,f(x) shown point of inflexion