For the following three reactions (i), (ii) and (iii), equilibrium constants are given (i) CO(g) + H2O(g) CO2(g) + H2(g) ; K1 (ii) CH4(g) + H2O(g) CO(g) 3H2(g) ; K2 (iii) CH4(g) + 2H2O(g) CO2(g) + 4H2(g) ; K 3 Which of the following relation is correct?

Question

For the following three reactions (i), (ii) and (iii), equilibrium constants are given (i) CO(g) + H2O(g) <=> CO2(g) + H2(g) ; K1 (ii) CH4(g) + H2O(g) <=> CO(g) 3H2(g) ; K2 (iii) CH4(g) + 2H2O(g) <=> CO2(g) + 4H2(g) ; K 3 Which of the following relation is correct? (A) K3 . L23 = K12 (B) K1 √K2 = K3 (C) K2K3 = K1 (D) K3 = K1 K2

Tardigrade Admin · Accepted Answer

Given reaction: (i) CO(g) + H2O(g) <=> CO2(g) + H2(g) ; K1 Equilibrium constant (K1)=([CO2][ H2]/[CO][H2O]) (ii) CH4(g) + H2O(g) <=> CO(g) 3H2(g) ; K2 Equilibrium constant (K2)=([CO][H2]3/[CH4][H2O]) (iii) CH4(g) + 2H2O(g) <=> CO2(g) + 4H2(g) ; K 3 Equilibrium constant (K3)=([CO2][H2]4/[CH4][H2O]2) So, K3=K1.K2

$K_{3} . L_{2}^{3} = K_{1}^{2}$

$K_{1} K_{2} = K_{3}$

$K_{2} K_{3} = K_{1}$

$K_{3} = K_{1} K_{2}$

K3​.L23​=K12​

K1​K2​​=K3​

K2​K3​=K1​

K3​=K1​K2​

$K_{3} . L_{2}^{3} = K_{1}^{2}$

$K_{1} K_{2} = K_{3}$

$K_{2} K_{3} = K_{1}$

$K_{3} = K_{1} K_{2}$