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Question
Mathematics
For the following probability distribution: X 1 2 3 4 P(X) (1/10) (1/5) (3/10) (2/5) E(X2) is equal to
Q. For the following probability distribution:
X
1
2
3
4
P(X)
10
1
5
1
10
3
5
2
E
(
X
2
)
is equal to
3488
189
Probability - Part 2
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A
3
17%
B
5
25%
C
7
0%
D
10
58%
Solution:
Σ
(
X
2
)
=
Σ
X
2
P
(
X
)
=
(
1
)
2
×
10
1
+
(
2
)
2
×
5
1
+
(
3
)
2
×
10
3
+
(
4
)
2
×
5
2
=
10
1
+
5
4
+
10
27
+
5
32
=
10
1
+
8
+
27
+
64
=
10
100
=
10