For the following concentration cell, to be spontaneous Pt ( H 2) P1 atm. mid HCl Pt ( H 2) P2 atm. Which of the following is correct?

Question

For the following concentration cell, to be spontaneous Pt ( H 2) P1 atm. mid HCl Pt ( H 2) P2 atm. Which of the following is correct? (A) P1=P2 (B) P1 < P2 (C) P1 > P2 (D) Can't be predicted

Tardigrade Admin · Accepted Answer

Pt ( H 2) P 1 atm. mid Pt ( H 2) P 2 atm. For spontaneous reaction, E cell should be positive so P1>P2 E cell =(0.059/2) log (P1/P2) Also, if P1>P2 oxidation occurs at L.H.S. electrode and reduction occurs at R.H.S. electrode.

Q. For the following concentration cell, to be spontaneous $Pt (H_{2}) P_{1}$ atm. $∣ H ClPt (H_{2}) P_{2} a t m$ . Which of the following is correct?

$P_{1} = P_{2}$

$P_{1} < P_{2}$

$P_{1} > P_{2}$

Can't be predicted

$Pt (H_{2}) P_{1}$ atm. $∣ Pt (H_{2}) P_{2} a t m$ .

For spontaneous reaction, $E_{ce ll}$ should be positive so $P_{1} > P_{2}$

$E_{ce ll} = \frac{0.059}{2} lo g \frac{P _{1}}{P _{2}}$

Also, if $P_{1} > P_{2}$ oxidation occurs at L.H.S. electrode and reduction occurs at R.H.S. electrode.

Q. For the following concentration cell, to be spontaneous Pt(H2​)P1​ atm. ∣HClPt(H2​)P2​atm. Which of the following is correct?

P1​=P2​

P1​<P2​

P1​>P2​