For the first order reaction A arrow B, the half life is 30 min. The time taken for 75 % completion of the reaction is min. (Nearest integer) Given: log g 2=0.3010 log 3=0.4771 log 5=0.6989

Question

For the first order reaction A arrow B, the half life is 30 min. The time taken for 75 % completion of the reaction is min. (Nearest integer) Given: log g 2=0.3010 log 3=0.4771 log 5=0.6989 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

t 1 / 2= T 50=30 min T 75=2 t 1 / 2=30 × 2=60 min

Q. For the first order reaction $A \to B$ , the half life is $30 min$ . The time taken for $75%$ completion of the reaction is min. (Nearest integer)
Given : $lo g_{g} 2 = 0.3010$
$lo g 3 = 0.4771$
$lo g 5 = 0.6989$

$t_{1/2} = T_{50} = 30 min$
$T_{75} = 2 t_{1/2} = 30 \times 2 = 60 min$

Q. For the first order reaction A→B, the half life is 30min. The time taken for 75% completion of the reaction is min. (Nearest integer) Given : logg​2=0.3010 log3=0.4771 log5=0.6989

t1/2​=T50​=30min T75​=2t1/2​=30×2=60min

Q. For the first order reaction $A \to B$ , the half life is $30 min$ . The time taken for $75%$ completion of the reaction is min. (Nearest integer)
Given : $lo g_{g} 2 = 0.3010$
$lo g 3 = 0.4771$
$lo g 5 = 0.6989$

$t_{1/2} = T_{50} = 30 min$
$T_{75} = 2 t_{1/2} = 30 \times 2 = 60 min$