For the equilibrium, A ( g ) leftharpoons B ( g ), Δ H is -40 kJ / mol. If the ratio of the activation energies of the forward (E f ) and reverse (E b ) reactions is (2/3) then:

Question

For the equilibrium, A ( g ) leftharpoons B ( g ), Δ H is -40 kJ / mol. If the ratio of the activation energies of the forward (E f ) and reverse (E b ) reactions is (2/3) then: (A) Ef = 60 kJ/mol ; Eb = 100 kJ /mol (B) Ef = 30 kJ/mol ; Eb = 70 kJ /mol (C) Ef = 80 kJ/mol ; Eb = 120 kJ /mol (D) Ef = 70 kJ/mol ; Eb = 30 kJ/mol

Tardigrade Admin · Accepted Answer

A ( g ) leftharpoons B ( g ) Δ H =-40 kJ Since, (E f /E b )=(2/3), therefore, E f =(2 x/5) and E b =(3 x/5) E b -E f =+40 (3 x/5)-(2 x/5)=+40 ⇒ (x/5)=40 ⇒ x=200 Therefore, E b =(3 x/5)=(3 × 200/5)=120 kJ mol -1 E f =(2 x/5)=(2 × 200/5)=80 kJ mol -1

Q. For the equilibrium, $A (g) ⇌ B (g), Δ H$ is $- 40 k J / m o l$ . If the ratio of the activation energies of the forward $(E_{f})$ and reverse $(E_{b})$ reactions is $\frac{2}{3}$ then:

$E_{f} = 60 k J / m o l$ ; $E_{b} = 100 k J / m o l$

$E_{f} = 30 k J / m o l$ ; $E_{b} = 70 k J / m o l$

$E_{f} = 80 k J / m o l$ ; $E_{b} = 120 k J / m o l$

$E_{f} = 70 k J / m o l$ ; $E_{b} = 30 k J / m o l$

Q. For the equilibrium, A(g)⇌B(g),ΔH is −40kJ/mol. If the ratio of the activation energies of the forward (Ef​) and reverse (Eb​) reactions is 32​ then:

Ef​=60kJ/mol ; Eb​=100kJ/mol

Ef​=30kJ/mol ; Eb​=70kJ/mol

Ef​=80kJ/mol ; Eb​=120kJ/mol

Ef​=70kJ/mol ; Eb​=30kJ/mol

A(g)⇌B(g)ΔH=−40kJ Since, Eb​Ef​​=32​, therefore, Ef​=52x​ and Eb​=53x​ Eb​−Ef​=+40 53x​−52x​=+40⇒5x​=40⇒x=200 Therefore, Eb​=53x​=53×200​=120kJmol−1 Ef​=52x​=52×200​=80kJmol−1

Q. For the equilibrium, $A (g) ⇌ B (g), Δ H$ is $- 40 k J / m o l$ . If the ratio of the activation energies of the forward $(E_{f})$ and reverse $(E_{b})$ reactions is $\frac{2}{3}$ then:

$E_{f} = 60 k J / m o l$ ; $E_{b} = 100 k J / m o l$

$E_{f} = 30 k J / m o l$ ; $E_{b} = 70 k J / m o l$

$E_{f} = 80 k J / m o l$ ; $E_{b} = 120 k J / m o l$

$E_{f} = 70 k J / m o l$ ; $E_{b} = 30 k J / m o l$