Tardigrade
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Tardigrade
Question
Chemistry
For the electrochemical cell, M |M+ ||X- | X, E°(M+/M) = 0.44V and E°(X/X-) = 0.33V From this data, one can deduce that
Q. For the electrochemical cell,
M
∣
M
+
∣∣
X
−
∣
X
,
E
∘
(
M
+
/
M
)
=
0.44
V
and
E
∘
(
X
/
X
−
)
=
0.33
V
From this data, one can deduce that
1814
240
Electrochemistry
Report Error
A
M
+
X
→
M
+
+
X
−
is the spontaneous reaction
25%
B
M
+
+
X
−
→
M
+
X
−
is the spontaneous reaction
43%
C
E
ce
ll
=
0.77
V
26%
D
E
ce
ll
=
−
0.77
V
6%
Solution:
M
∣
M
+
∣∣
X
∣
X
−
, Cell reaction should be
M
+
X
→
M
+
+
X
−
E
cell
∘
=
E
cathode
∘
−
E
anode
∘
=
0.33
−
0.44
=
−
0.11
V
∴
Reverse cell reaction should be spontaneous i.e.
M
+
+
X
−
→
M
+
X