For the decomposition of hydrogen iodide at 127° C , the fraction of molecules having energy equal to or greater than activation energy can be given as

Question

For the decomposition of hydrogen iodide at 127° C , the fraction of molecules having energy equal to or greater than activation energy can be given as (A) e(-Ea/2.303 R)  (B) e(-Ea/920 R) (C) 10(- E a /2.303 R )  (D) 10(- E a /921.2 R )

Tardigrade Admin · Accepted Answer

Fraction of molecules = e (- E a / RT ) =(- E a /102.303 RT ) =10(- E a /2.303 × R × 400) =10(- E a /921.2 R)

Q. For the decomposition of hydrogen iodide at $12 7^{\circ} C,$ the fraction of molecules having energy equal to or greater than activation energy can be given as

$e^{\frac{- E _{a}}{2.303 R}}$

$e^{\frac{- E _{a}}{920 R}}$

$1 0^{\frac{- E _{a}}{2.303 R}}$

$1 0^{\frac{- E _{a}}{921.2 R}}$

Fraction of molecules $= e^{\frac{- E _{a}}{RT}}$

$= \frac{- E _{a}}{1 0 ^{2.303 RT}}$

$= 1 0^{\frac{- E _{a}}{2.303 \times R \times 400}}$

$= 1 0^{\frac{- E _{a}}{921.2 R}}$

Q. For the decomposition of hydrogen iodide at 127∘C, the fraction of molecules having energy equal to or greater than activation energy can be given as

e2.303R−Ea​​

e920R−Ea​​

102.303R−Ea​​

10921.2R−Ea​​