Q. For the circuit shown in the figure, the current I will be

40457 212 NEETNEET 2020Current Electricity Report Error

A

$0.75 A$

5%

B

$1 A$

78%

C

$1.5 A$

11%

D

$0.5 A$

5%

Solution:

$I = \frac{2 + 4}{4 + 1 + 1} = \frac{6}{6} = 1 A m p$