For the circuit shown below, the current (in mA ) through the Zener diode is

Question

For the circuit shown below, the current (in mA ) through the Zener diode is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-r4slj56h1zl0.png" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-r4slj56hlz6z.png" /> Current through 5kΩ i1=(70/5000)=14mA Current through 10kΩ iL=(50/10 , 000)=5mA Current through Zennor diode I=9mA

Q. For the circuit shown below, the current (in $m A$ ) through the Zener diode is

Current through $5 k Ω$
$i_{1} = \frac{70}{5000} = 14 m A$
Current through $10 k Ω$
$i_{L} = \frac{50}{10 , 000} = 5 m A$
Current through Zennor diode $I = 9 m A$

Q. For the circuit shown below, the current (in mA ) through the Zener diode is

Current through 5kΩ i1​=500070​=14mA Current through 10kΩ iL​=10,00050​=5mA Current through Zennor diode I=9mA

Q. For the circuit shown below, the current (in $m A$ ) through the Zener diode is

Current through $5 k Ω$
$i_{1} = \frac{70}{5000} = 14 m A$
Current through $10 k Ω$
$i_{L} = \frac{50}{10 , 000} = 5 m A$
Current through Zennor diode $I = 9 m A$