For the chemical reaction N2(g)+3 H2(g) leftharpoons 2 N3(g) the correct option is:

Question

For the chemical reaction N2(g)+3 H2(g) leftharpoons 2 N3(g) the correct option is: (A) -(d[N2]/dt)=(1/2)(d[NH3]/dt) (B) 3(d[H2]/dt)=2(d[NH3]/dt) (C) -(1/3)(d[H2]/dt)=2(d[NH3]/dt) (D) -(d[N2]/dt)=2(d[NH3]/dt)

Tardigrade Admin · Accepted Answer

N 2+3 H 2 leftharpoons 2 NH 3 Rate of reaction is given as -(d[N2]/d t)=-(1/3) (d[H2]/d t)=+(1/2) (d[N H H3]/d t)

Q. For the chemical reaction $N_{2 (g)} + 3 H_{2 (g)} ⇌ 2 N_{3 (g)}$ the correct option is:

$- \frac{d [ N _{2} ]}{d t} = \frac{1}{2} \frac{d [ N H _{3} ]}{d t}$

$3 \frac{d [ H _{2} ]}{d t} = 2 \frac{d [ N H _{3} ]}{d t}$

$- \frac{1}{3} \frac{d [ H _{2} ]}{d t} = 2 \frac{d [ N H _{3} ]}{d t}$

$- \frac{d [ N _{2} ]}{d t} = 2 \frac{d [ N H _{3} ]}{d t}$

$N_{2} + 3 H_{2} ⇌ 2 N H_{3}$
Rate of reaction is given as
$- \frac{d [ N _{2} ]}{d t} = - \frac{1}{3} \frac{d [ H _{2} ]}{d t} = + \frac{1}{2} \frac{d [ N H H _{3} ]}{d t}$

Q. For the chemical reaction N2(g)​+3H2(g)​⇌2N3(g)​ the correct option is:

−dtd[N2​]​=21​dtd[NH3​]​

3dtd[H2​]​=2dtd[NH3​]​

−31​dtd[H2​]​=2dtd[NH3​]​

−dtd[N2​]​=2dtd[NH3​]​