For the cell reaction 2 Ce4++Co arrow 2 Ce3++Co3+ ; E°cell cell is 1.89 V. If ECo2+/Co is - 0.28 V, what is the value of E° Ce4+/Ce 3+ ?

Question

For the cell reaction 2 Ce4++Co arrow 2 Ce3++Co3+ ; E°cell cell is 1.89 V. If ECo2+/Co is - 0.28 V, what is the value of E° Ce4+/Ce 3+ ? (A) 0.28 V (B) 1.61 V (C) 2.17 V (D) 5.29 V

Tardigrade Admin · Accepted Answer

E text cell °=E text ox °+E text red °=-E Co / Co 2+°+E Ce 4+ / Ce 3+ 1.89=-(-0.28)+E Ce 4+ / Ce 3+° ∴ E Ce 4+ / Ce 3+°=1.89-0.28=1.61 V

Q. For the cell reaction $2 C e^{4 +} + C o \to 2 C e^{3 +} + C o^{3 +}; E_{ce ll}^{\circ}$ cell is $1.89 V$ . If $E_{C o^{2 +} / C o}$ is $- 0.28 V$ , what is the value of $E_{C e^{4 +} / C e^{3 +}}^{\circ}$ ?

0.28 V

1.61 V

2.17 V

5.29 V

$E_{cell}^{\circ} = E_{ox}^{\circ} + E_{red}^{\circ} = - E_{C o / C o^{2 +}}^{\circ} + E_{C e^{4 +} / C e^{3 +}}$
$1.89 = - (- 0.28) + E_{C e^{4 +} / C e^{3 +}}^{\circ}$
$∴ E_{C e^{4 +} / C e^{3 +}}^{\circ} = 1.89 - 0.28 = 1.61 V$

Q. For the cell reaction 2Ce4++Co→2Ce3++Co3+;Ecell∘​ cell is 1.89V. If ECo2+/Co​ is −0.28V, what is the value of ECe4+/Ce3+∘​?