Question

For the calculation, $(3.00\times 2.303)+10.00=?$, the number of significant figures in final answer is_______.

Answer 1

Answer: 4

In multiplication, the result is reported with the same number of significant figures as there are in the measurement with the few significant figures.
Hence, $(3.00\times 2.303)=6.90$
In addition, the maximum number of digits to the right of the decimal point in the result should not be greater than any of the numbers taking part in calculations.
Hence, $6.90+10.00$ $=16.90$.
Hence, there are $4$ significant figures in final answer.