Q. For the Balmer series in the spectrum of H atom, the correct statements among (I) to (IV) are:
(I) As wavelength decreases, the lines in the series converge
(II) The integer is equal to 2
(III) The lines of longest wavelength corresponds to
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines

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Solution:


\overline{ v }= R _{ H }\left[\frac{1}{ n _{1}^{2}}-\frac{1}{ n _{2}^{2}}\right]

(I) As the wavelength decreases the energy increases therefore the spectrum lines become bond and formed a converging series.
(II) For balmer series always started ground state
(III) At longest wavelength, the higher state energy will be minimum therefore excited state will be nest to the ground always.
(IV) for aton
So, we cannot find ionization energy directly by only ware number, we also required transition state(n) value.
According to the above observation
Only (I), (II) and (III) correct.