For the acceleration-time (a-t) graph shown in figure, the change in velocity of particle from t=0 to t=6 s is

Question

For the acceleration-time (a-t) graph shown in figure, the change in velocity of particle from t=0 to t=6 s is (A) 10 m / s (B) 4 m / s (C) 12 m / s (D) 8 m / s

Tardigrade Admin · Accepted Answer

Area under a-t graph gives change in velocity. So, Δ v=(1/2) × 4 × 4-(1/2) × 2 × 4=8-4 Δ v=4 ms -1

Q. For the acceleration-time (a-t) graph shown in figure, the change in velocity of particle from $t = 0$ to $t = 6 s$ is

10 m / s

4 m / s

12 m / s

8 m / s

Area under $a - t$ graph gives change in velocity.
So, $Δ v = \frac{1}{2} \times 4 \times 4 - \frac{1}{2} \times 2 \times 4 = 8 - 4$
$Δ v = 4 m s^{- 1}$

Q. For the acceleration-time (a-t) graph shown in figure, the change in velocity of particle from t=0 to t=6s is