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Relations and Functions - Part 2
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Solution:
Given that f(x)=x3+5x+1 ∴f′(x)=3x2+5>0,∀x∈R ⇒f(x) is strictly increasing on R ⇒f(x) is one one ∴ Being a polynomial f (x) is continuous and increasing.
on R with x→∞limf(x)=−∞ and x→∞limf(x)=∞ ∴ Range of f=(−∞,∞)=R
Hence f is onto also. So, f is one one and onto R.