For real gases, the relation between P, V and T is given by van der Waals equation, (P + (a n2/V2))(V - n b)=nRT. For the following gases CH4,CO2,O2,H2 which gas will have (i) highest value of 'a' and (ii) lowest value of 'b' respectively?

Question

For real gases, the relation between P, V and T is given by van der Waals equation, (P + (a n2/V2))(V - n b)=nRT. For the following gases CH4,CO2,O2,H2 which gas will have (i) highest value of 'a' and (ii) lowest value of 'b' respectively? (A) (i) CO2 , (ii) H2 (B) (i) CH4 , (ii) CO2 (C) (i) H2 , (ii) CO2 (D) (i) O2 , (ii) H2

Tardigrade Admin · Accepted Answer

(i) Order of intermolecular attraction is

C O_{2} > C H_{4} > O_{2} > H_{2}

In

C O_{2}

value of '

a

' will be maximum. Value of '

a

' is directly proportional to intermolecular attraction of gas molecules.
(ii) Size increases in order of

H_{2} < O_{2} < C H_{4} < C O_{2}

Hence,

H_{2}

will have lowest value of '

b

'. Value of '

b

' is directly proportional to molecular size of gas molecules.

Q. For real gases, the relation between P, V and T is given by van der Waals equation, $(P + \frac{a n ^{2}}{V ^{2}}) (V - nb) = n RT .$ For the following gases $C H_{4}, C O_{2}, O_{2}, H_{2}$ which gas will have
(i) highest value of ' $a$ ' and (ii) lowest value of ' $b$ ' respectively?

(i) $C O_{2}$ , (ii) $H_{2}$

(i) $C H_{4}$ , (ii) $C O_{2}$

(i) $H_{2}$ , (ii) $C O_{2}$

(i) $O_{2}$ , (ii) $H_{2}$

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(i) CO2​ , (ii) H2​

(i) CH4​ , (ii) CO2​

(i) H2​ , (ii) CO2​

(i) O2​ , (ii) H2​

Q. For real gases, the relation between P, V and T is given by van der Waals equation, $(P + \frac{a n ^{2}}{V ^{2}}) (V - nb) = n RT .$ For the following gases $C H_{4}, C O_{2}, O_{2}, H_{2}$ which gas will have
(i) highest value of ' $a$ ' and (ii) lowest value of ' $b$ ' respectively?

(i) $C O_{2}$ , (ii) $H_{2}$

(i) $C H_{4}$ , (ii) $C O_{2}$

(i) $H_{2}$ , (ii) $C O_{2}$

(i) $O_{2}$ , (ii) $H_{2}$