For orthorhombic system axial ratios are a ≠ b ≠ c and the axial angles are

Question

For orthorhombic system axial ratios are a ≠ b ≠ c and the axial angles are (A) α = β = &gamma; ≠ 90° (B) α = β = &gamma; = 90° (C) α = &gamma; = 90°, β ≠ 90° (D) α ≠ β ≠ &gamma; ≠ 90°

Tardigrade Admin · Accepted Answer

Orthorhombic crystal has three unequal axis which are at right angle to each other a ≠ b ≠ c, all angles = 90° So, axial distances a ≠ b ≠ c, and axial angles a = p = y = 90°

Q. For orthorhombic system axial ratios are $a \neq = b \neq = c$ and the axial angles are

$α = β = γ \neq = 9 0^{\circ}$

$α = β = γ = 9 0^{\circ}$

$α = γ = 9 0^{\circ}, β \neq = 9 0^{\circ}$

$α \neq = β \neq = γ \neq = 9 0^{\circ}$

Orthorhombic crystal has three unequal axis
which are at right angle to each other $a \neq = b \neq = c,$ all
angles = $9 0^{\circ}$
So, axial distances $a \neq = b \neq = c,$ and axial angles
a = p = y = $9 0^{\circ}$

Q. For orthorhombic system axial ratios are a=b=c and the axial angles are

α=β=γ=90∘

α=β=γ=90∘

α=γ=90∘,β=90∘

α=β=γ=90∘