For one mole of NaCl(s) the lattice enthalpy is

Question

For one mole of NaCl(s) the lattice enthalpy is (A) -788 kJ/mol (B) +878 kJ/mol (C) +788 kJ/mol (D) -878 kJ/mol

Tardigrade Admin · Accepted Answer

Δ /H° = S + D +J.E.+ E.A. + U - 411.2 = 108.4 + 121 + 495.6 - 348.6 + U U = - 787.6 kJ/mol = - 788 kJ/mol

Q. For one mole of $N a C l_{(s)}$ the lattice enthalpy is