Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
For L.P.P, maximize z = 4x1+ 2x2 subject to 3x1 + 2x2 ge 9, x1 - x2 le 3, x1 ge 0, x2 ge 0 has .........
Q. For
L
.
P
.
P
, maximize
z
=
4
x
1
+
2
x
2
subject to
3
x
1
+
2
x
2
≥
9
,
x
1
−
x
2
≤
3
,
x
1
≥
0
,
x
2
≥
0
has .........
1978
192
MHT CET
MHT CET 2019
Report Error
A
infinite number of optimal solutions
B
unbounded solution
C
no solution
D
one optimal solution
Solution:
We have, maximise
z
=
4
x
1
+
2
x
2
Subject to constracts,
3
x
1
+
2
x
2
≥
9
,
x
1
−
x
2
≤
3
x
1
≥
0
,
x
2
≥
0
On taking given constraints as equation, we get the following graphs
Here, we get feasible region Is unbounded.