For Freundlich isotherm a graph of log (x/m) is plotted against log P. The slope of the line and its y-axis intercept, respectively corresponds to

Question

For Freundlich isotherm a graph of log (x/m) is plotted against log P. The slope of the line and its y-axis intercept, respectively corresponds to (A)  log (1/n),k (B)  log (1/n), log k (C)  (1/n), k (D) (1/n), log k

Tardigrade Admin · Accepted Answer

According to Freundlich adsorption isotherm (x/m)=k p1 / n Taking log both side log (x/m)=(1/n) log p+ log k <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/f2df1179dd348fc395cde1af7db70c30-.png" /> Graph between log (x/-) against log p

Q. For Freundlich isotherm a graph of log $\frac{x}{m}$ is plotted against $l o g P$ . The slope of the line and its y-axis intercept, respectively corresponds to

$lo g \frac{1}{n}, k$

$lo g \frac{1}{n}, lo g k$

$\frac{1}{n}, k$

$\frac{1}{n}, lo g k$

According to Freundlich adsorption isotherm

$\frac{x}{m} = k p^{1/ n}$

Taking log both side

$lo g \frac{x}{m} = \frac{1}{n} lo g p + lo g k$

Graph between $lo g \frac{x}{-}$ against $lo g p$

Q. For Freundlich isotherm a graph of log mx​ is plotted against logP. The slope of the line and its y-axis intercept, respectively corresponds to

logn1​,k

logn1​,logk

n1​,k

n1​,logk