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Chemistry
For Freundlich isotherm a graph of log (x/m) is plotted against log P. The slope of the line and its y-axis intercept, respectively corresponds to
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Q. For Freundlich isotherm a graph of log $\frac {x}{m}$ is plotted against $log\, P$. The slope of the line and its y-axis intercept, respectively corresponds to
KCET
KCET 2014
Surface Chemistry
A
$ \log \frac{1}{n},k$
12%
B
$\log \frac{1}{n},\log k$
25%
C
$\frac {1}{n}, k$
10%
D
$\frac{1}{n}, \log k$
53%
Solution:
According to Freundlich adsorption isotherm
$\frac{x}{m}=k p^{1 / n}$
Taking log both side
$\log \frac{x}{m}=\frac{1}{n} \log p+\log k$
Graph between $\log \frac{x}{-}$ against $\log p$