Question

For Freundlich adsorption isotherm, a plot of $\log (x/m)$ (y-axis) VS $\log p(x-$ axis) gives a straight line. The intercept and slope for the line are $0.4771$ and $2$, respectively. The mass of the gas, adsorbed per gram of adsorbent is $A\times 10^{-4}g$. if the intitial pressure is $0.04atm$ and $(\log 3=0.4771)$ The value of $A$ is

Answer 1

Answer: 48

$x/m=K{P}^{1/n}$
$\log (x/m)=\log (k)+\frac{1}{n}\log (P)$
$K=3,\frac{1}{n}=2\Rightarrow n=\frac{1}{2}$
$x/m=3(P{)}^{1/n}$
$x/m=3\times {\left(4\times 10^{-2}\right)}^2$
$=48\times 10^{-4}g$