For d-block elements the first ionization potential is of the order

Question

For d-block elements the first ionization potential is of the order (A) Zn>Fe>Cu>Cr (B) Sc=TiCr>Mn>Fe

Tardigrade Admin · Accepted Answer

Key Idea: The ionisation energies increase with increasing atomic number. The trend is irregular among d-block elements
Element
Sc
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
IE

(k J / m o l^{- 1})

631
656
650
652
717
762
758
736
745
905

∴

Z n > F e > C u > C r

is correct order.

Q. For d-block elements the first ionization potential is of the order

$Z n > F e > C u > C r$

$S c = T i < V = C r$

$Z n < C u < N i < C o$

$V > C r > M n > F e$

Key Idea: The ionisation energies increase with increasing atomic number. The trend is irregular among d-block elements
Element
Sc
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
IE $(k J / m o l^{- 1})$
631
656
650
652
717
762
758
736
745
905
$∴$ $Z n > F e > C u > C r$ is correct order.

Q. For d-block elements the first ionization potential is of the order

Zn>Fe>Cu>Cr

Sc=Ti<V=Cr

Zn<Cu<Ni<Co

V>Cr>Mn>Fe

Key Idea: The ionisation energies increase with increasing atomic number. The trend is irregular among d-block elements Element Sc Ti V Cr Mn Fe Co Ni Cu Zn IE (kJ/mol−1) 631 656 650 652 717 762 758 736 745 905 ∴ Zn>Fe>Cu>Cr is correct order.

$Z n > F e > C u > C r$

$S c = T i < V = C r$

$Z n < C u < N i < C o$

$V > C r > M n > F e$

Key Idea: The ionisation energies increase with increasing atomic number. The trend is irregular among d-block elements
Element
Sc
Ti
V
Cr
Mn
Fe
Co
Ni
Cu
Zn
IE $(k J / m o l^{- 1})$
631
656
650
652
717
762
758
736
745
905
$∴$ $Z n > F e > C u > C r$ is correct order.