For d block elements the first ionization potential is of the order :

Question

For d block elements the first ionization potential is of the order : (A) Zn > Fe >Cu > Cr (B) Sc = Ti < V = Cr (C) Zn < Cu < Ni < Co (D) V > Cr > Mn > Fe

Tardigrade Admin · Accepted Answer

The ionisation energies increase with increase with atom number. The trend is irregular among

d

-block elements.

Element I E (kj / m o l^{- 1}) S c 631 T i 656 V 650 C r 652 M n 717 F e 762 C o 758 N i 736 C u 745 Z n 905

∴ Z n > F e > C u > C r

is correct order

Q. For $d$ block elements the first ionization potential is of the order :

$Z n > F e > C u > C r$

$S c = T i < V = C r$

$Z n < C u < N i < C o$

$V > C r > M n > F e$

The ionisation energies increase with increase with atom number. The trend is irregular among $d$ -block elements.

$Element I E (kj / m o l^{- 1}) S c 631 T i 656 V 650 C r 652 M n 717 F e 762 C o 758 N i 736 C u 745 Z n 905$

$∴ Z n > F e > C u > C r$ is correct order

Q. For d block elements the first ionization potential is of the order :

Zn>Fe>Cu>Cr

Sc=Ti<V=Cr

Zn<Cu<Ni<Co

V>Cr>Mn>Fe