For complexes [NiCl4]2- and Ni(CO)4 which one of the following statement is true

Question

For complexes [NiCl4]2- and Ni(CO)4 which one of the following statement is true (A)  [NiCl4]2- is diamagnetic while [Ni(CO)4] is paramagnetic and both the complexes have square planar geometry (B)  [NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic and both the complexes have tetrahedral geometry (C)  [NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic and both the complexes have square planar geometry (D)  [NiCl4]2- is diamagnetic while [Ni(CO)4] is paramagnetic and both the complexes have tetrahedral geometry

Tardigrade Admin · Accepted Answer

[NiCl4]2- Configuration:

Oxidation state of metal = + 2 Type of hybridisation = sp3 (tetrahedral) Number of unpaired electrons = 2 Magnetic nature = Paramagnetic [Ni(CO)4] Configuration:

Oxidation state of metal = O Type of hybridisation = sp3 (tetrahedral) Number of unpaired electrons = O Magnetic nature = Diamagnetic Hence, [NiCl4]2- is paramagnetic while [Ni(CO)4] is diamagnetic and both the complexes have tetrahedral geometry.

Q. For complexes $[N i C l_{4}]^{2 -}$ and $N i (CO)_{4}$ which one of the following statement is true

$[N i C l_{4}]^{2 -}$ is diamagnetic while $[N i (CO)_{4}]$ is paramagnetic and both the complexes have square planar geometry

$[N i C l_{4}]^{2 -}$ is paramagnetic while $[N i (CO)_{4}]$ is diamagnetic and both the complexes have tetrahedral geometry

$[N i C l_{4}]^{2 -}$ is paramagnetic while $[N i (CO)_{4}]$ is diamagnetic and both the complexes have square planar geometry

$[N i C l_{4}]^{2 -}$ is diamagnetic while $[N i (CO)_{4}]$ is paramagnetic and both the complexes have tetrahedral geometry

Q. For complexes [NiCl4​]2− and Ni(CO)4​ which one of the following statement is true

[NiCl4​]2− is diamagnetic while [Ni(CO)4​] is paramagnetic and both the complexes have square planar geometry

[NiCl4​]2− is paramagnetic while [Ni(CO)4​] is diamagnetic and both the complexes have tetrahedral geometry

[NiCl4​]2− is paramagnetic while [Ni(CO)4​] is diamagnetic and both the complexes have square planar geometry

[NiCl4​]2− is diamagnetic while [Ni(CO)4​] is paramagnetic and both the complexes have tetrahedral geometry

Q. For complexes $[N i C l_{4}]^{2 -}$ and $N i (CO)_{4}$ which one of the following statement is true

$[N i C l_{4}]^{2 -}$ is diamagnetic while $[N i (CO)_{4}]$ is paramagnetic and both the complexes have square planar geometry

$[N i C l_{4}]^{2 -}$ is paramagnetic while $[N i (CO)_{4}]$ is diamagnetic and both the complexes have tetrahedral geometry

$[N i C l_{4}]^{2 -}$ is paramagnetic while $[N i (CO)_{4}]$ is diamagnetic and both the complexes have square planar geometry

$[N i C l_{4}]^{2 -}$ is diamagnetic while $[N i (CO)_{4}]$ is paramagnetic and both the complexes have tetrahedral geometry