For combustion of one mole of magnesium in an open container at 300 K and 1 bar pressure, Δ C H Θ =-601.70 kJ mol -1, the magnitude of change in internal energy for the reaction is KJ(Nearest integer) (Given: R =8.3 J K -1 mol -1 )

Question

For combustion of one mole of magnesium in an open container at 300 K and 1 bar pressure, Δ C H Θ =-601.70 kJ mol -1, the magnitude of change in internal energy for the reaction is KJ(Nearest integer) (Given: R =8.3 J K -1 mol -1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Mg ( s )+(1/2) O 2( g ) arrow MgO ( s ) Δ H =Δ U +Δ n g RT -601.70 × 103=Δ U -(1/2) × 8.3 × 300 -601.70 kJ =Δ U -1.245 kJ Δ U =-600.455 kJ Ans. 600

Q. For combustion of one mole of magnesium in an open container at $300 K$ and $1$ bar pressure, $Δ_{C} H^{Θ}$ $= - 601.70 k J m o l^{- 1}$ , the magnitude of change in internal energy for the reaction is ____ $K J$ (Nearest integer) (Given $: R = 8.3 J K^{- 1} m o l^{- 1}$ )

$M g (s) + \frac{1}{2} O_{2} (g) \to M g O (s)$
$Δ H = Δ U + Δ n_{g} RT$
$- 601.70 \times 1 0^{3} = Δ U - \frac{1}{2} \times 8.3 \times 300$
$- 601.70 k J = Δ U - 1.245 k J$
$Δ U = - 600.455 k J$
Ans. $600$

Q. For combustion of one mole of magnesium in an open container at 300K and 1 bar pressure, ΔC​HΘ =−601.70kJmol−1, the magnitude of change in internal energy for the reaction is ____KJ(Nearest integer) (Given :R=8.3JK−1mol−1 )

Mg(s)+21​O2​(g)→MgO(s) ΔH=ΔU+Δng​RT −601.70×103=ΔU−21​×8.3×300 −601.70kJ=ΔU−1.245kJ ΔU=−600.455kJ Ans. 600

Q. For combustion of one mole of magnesium in an open container at $300 K$ and $1$ bar pressure, $Δ_{C} H^{Θ}$ $= - 601.70 k J m o l^{- 1}$ , the magnitude of change in internal energy for the reaction is ____ $K J$ (Nearest integer) (Given $: R = 8.3 J K^{- 1} m o l^{- 1}$ )

$M g (s) + \frac{1}{2} O_{2} (g) \to M g O (s)$
$Δ H = Δ U + Δ n_{g} RT$
$- 601.70 \times 1 0^{3} = Δ U - \frac{1}{2} \times 8.3 \times 300$
$- 601.70 k J = Δ U - 1.245 k J$
$Δ U = - 600.455 k J$
Ans. $600$